Determine the adiabatic saturation temperature of air at the following conditions:
Dry-bulb temperature 22 C
Wet-bulb temperature (sling) 14 C
Atmospheric pressure 1.013 bar
An adiabatic process is defined as a process in which no external heat enters or leaves the system under consideration. Adiabatic humidification process: Air is flowing through a perfectly insulated duct with an open water tank in the bottom of it. If the tank is infinitely long, the air at the outlet will be 100% saturated.
Inlet: dry-bulb temperature T1 and moisture content g1
Outlet: dry-bulb temperature T2 and moisture content g2
We may write:
h1 = h2
or Sensible heat loss = Latent heat gain i.e.
Cp * ( T1 - T2 ) = Hfg * ( g2 - g1 )
Inputs |
Units |
||
Dry-bulb temperature = T1 = Td |
22,0 |
C |
|
Wet-bulb temperature |
14,0 |
C |
|
Atmospheric pressure |
1,013 |
C |
|
Outputs |
|||
Moisture content = g1 = InletMC |
0,0066 |
kg/kg |
|
Spec. heat capacity at inlet = Cp |
1,0102 |
kJ/(kg.K) |
|
Spec. enthalpy at inlet = InletH |
38,7042 |
kJ/kg |
|
Assume that adiabatic saturation | . | . | |
temperature Tsat, is 30 degC |
13,7920 |
C |
Assumed |
Saturated air has the same temp. | . | . | |
for dry and wet bulb which results | . | . | |
into the following | . | . | |
moisture content at outlet=OutletMC |
0,0098 |
kg/kg |
|
Now the enthalpy at outlet can be | . | . | |
calculated. OutletH is: |
38,7043 |
kJ/kg |
|
We know that in an adiabatic | . | . | |
process diff = OutletH - InletH = 0 |
0,0001 |
. |
Goal |
Now, use the solver to adjust cell | . | . | |
Tsat, until the goal cell | . | . | |
diff is zero. | . | . | |
Adiabatic Saturation Temp. =Tsat |
13,8 |
C |